Word Problem Solver

Turn a “find the number” word problem into an equation and solve it. Pick the phrasing, enter the numbers, and this word problem solver builds the linear equation and works through every step — like 10 added to four times a number is 46.

added to × a number is

The three boxes fill the blanks left to right. Switch the phrasing above to change what the words between them say.

Your problem & equation
The number

How to Turn a Word Problem Into an Equation

The trick to every “find the number” problem is translating the words into algebra, one phrase at a time.

1

Name the unknown

Let the number you’re looking for be x. Every “a number” in the sentence becomes that same x.

2

Translate phrase by phrase

“Four times a number” is 4x, “10 added to” means + 10, and “is” (or “the result is”) becomes =. So 10 added to four times a number is 46 becomes 4x + 10 = 46.

3

Undo the operations

Peel the equation back in reverse: subtract 10 (4x = 36), then divide by 4 (x = 9). The solver shows each step and checks the answer. Solving two unknowns instead? Use the System of Equations Solver; for ax²+bx+c=0 see the Quadratic Formula Calculator.

Frequently Asked Questions

If 10 is added to four times a number, the result is 46 — what is the number?
The number is 9. Let the number be x. “Four times a number” is 4x, and “10 added to” it gives 4x + 10, which equals 46. Subtract 10 from both sides to get 4x = 36, then divide by 4 to get x = 9. Check: 4 × 9 + 10 = 46. Change the result value in the solver to solve the same phrasing for any total.
How do you turn a word problem into an equation?
Let the unknown be a letter, usually x. Then translate the words phrase by phrase: “a number” becomes x, “four times a number” becomes 4x, “10 added to” means + 10, “subtracted from” means − , and “is” or “the result is” becomes =. Assemble the pieces in order and you have a linear equation you can solve by undoing each operation.
What kinds of word problems does this solver handle?
One-unknown linear number problems in four common phrasings: a constant added to a multiple of a number, a constant subtracted from a multiple of a number, a multiple of the sum of a number and a constant, and a multiple of the difference of a number and a constant. It is built for the classic algebra “find the number” questions rather than problems with several unknowns.
Does the word problem solver show the steps?
Yes. It shows the equation it built, then each algebra step down to the solution, gives the exact answer as a fraction (and a decimal when it is not a whole number), and finishes with a substitution check so you can confirm the number really works.