Quantum

The Bohr Model, Line by Line

By Lucian — builder & engineer, LK Forge

Heat hydrogen and it does not glow in a smear of colour — it emits a handful of razor-sharp lines, always in the same places. In 1913 Niels Bohr explained them with one bold idea: the electron can only sit on a ladder of fixed energies, and light comes out when it jumps between rungs. We took the Bohr lab’s formula, checked its colours against real hydrogen, and pulled a fundamental constant out of the slope.

 ·  6 min read  ·  exact from Eₙ = −13.6/n²

Eₙ = −13.6/n²
hydrogen’s energy ladder, in electron-volts
656.5 nm
the red Hα line — real hydrogen is 656.3 (0.03%)
1.097×10⁷ m⁻¹
the Rydberg constant, recovered from the lines
4 colours
why hydrogen glows in just these visible Balmer lines

The four colours of hydrogen

This is what you see through a spectroscope pointed at a hydrogen tube: a black band crossed by four bright lines, nothing in between. Each is one Balmer jump, placed by the model exactly where the real line sits. The same four lines, formed in the atmospheres of stars, are how we know the universe is mostly hydrogen.

Hα 656.5 Hβ 486.3 Hγ 434.2 Hδ 410.3 400 nm500 nm600 nm700 nm

The Balmer series on a 380–740 nm strip. Bohr places them at 656.5 / 486.3 / 434.2 / 410.3 nm; the real hydrogen lines are 656.3 / 486.1 / 434.0 / 410.2 — a match to two or three parts in ten thousand.

One slope, one constant

Every hydrogen line, in every series, obeys 1/λ = R·(1/n_lo² − 1/n_hi²). Plot the inverse wavelength against that bracket for jumps drawn from the Lyman, Balmer and Paschen series and they fall on a single straight line through the origin. Its slope is the Rydberg constant — the same number whether the line is ultraviolet, visible or infrared.

0.00 0.25 0.50 0.75 1.00 slope = R = 1.097×10⁷ m⁻¹ 2→1 3→1 3→2 4→2 5→2 4→3 5→3 0.000.250.500.75 1/n_lo² − 1/n_hi² → 1/λ (10⁷ m⁻¹)

Seven transitions (dots) from three series, all on one line whose slope is R = 1.097×10⁷ m⁻¹ — because R is nothing but 13.6 eV divided by hc.

Three series, three bands of light

Which rung the electron lands on decides the colour of the whole family. Only the Balmer series (landing on n = 2) falls in visible light — an accident of hydrogen’s energy spacing that made it the first spectrum ever decoded.

SeriesLands onFirst lineBandSeries limit
Lyman n = 1 121.6 nm ultraviolet 91.2 nm
Balmer n = 2 656.5 nm visible 364.7 nm
Paschen n = 3 1875.6 nm infrared 820.6 nm

The series limit (n_hi → ∞) is where the lines crowd together and stop — the ionisation edge. Balmer’s limit at 364.7 nm sits just past the violet, at the edge of sight.

Reproduce it yourself

The whole spectrum is two lines of arithmetic; the third pulls out the Rydberg constant.

const E = n => -13.6 / (n * n);                       // eV
const dE = (hi, lo) => 13.6 * (1/(lo*lo) - 1/(hi*hi)); // eV
const lambda = (hi, lo) => 1240 / dE(hi, lo);          // nm

lambda(3, 2);   // 656.5 nm  Hα (red)     real 656.3
lambda(4, 2);   // 486.3 nm  Hβ (cyan)    real 486.1

// Rydberg constant = slope of (1/lambda) vs (1/lo^2 - 1/hi^2):
const R = (1 / (lambda(3,2) * 1e-9)) / (1/4 - 1/9);   // 1.097e7 /m

The energy-level and wavelength formulas are lifted straight from the Bohr solver; the series table and Rydberg fit are the small script behind this post.

Build a spectrum

Open the lab, pick a series, and fire transitions one by one to watch each line appear on the spectrum exactly where the ladder puts it.

Open the Bohr lab →
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Common questions

What are the visible lines in hydrogen’s spectrum?

They are the Balmer series — electron jumps that land on the n = 2 level. The Bohr model puts them at 656.5 nm (Hα, red), 486.3 nm (Hβ, cyan), 434.2 nm (Hγ, violet) and 410.3 nm (Hδ, violet), and those match the real measured hydrogen wavelengths to within 0.05%. They are the only hydrogen lines in the visible band; jumps that land on n = 1 fall in the ultraviolet (Lyman series) and those landing on n = 3 in the infrared (Paschen series).

How does the Bohr model predict a spectral line’s wavelength?

Each level has energy Eₙ = −13.6/n² eV. A jump from a high level n_hi to a lower n_lo releases the difference as a photon, ΔE = 13.6·(1/n_lo² − 1/n_hi²) eV, and the wavelength follows from λ = 1240/ΔE nm (using hc = 1240 eV·nm). For the 3 → 2 jump that is 13.6·(1/4 − 1/9) = 1.89 eV, giving 656.5 nm — the red line you see through a hydrogen discharge tube.

What is the Rydberg constant and can this recover it?

The Rydberg constant R sets the scale of every hydrogen line through 1/λ = R·(1/n_lo² − 1/n_hi²). Plotting 1/λ against that bracket for many transitions gives a straight line through the origin whose slope is R. From the Bohr numbers here the slope comes out at 1.09677×10⁷ per metre — indistinguishable from the accepted 1.0967758×10⁷ — because R is just 13.6 eV divided by hc, the two constants the model is built from.